Solved Find The Particular Solution Of Y 2x 2 Xy Y 2 Dx X 2 2x 1 Dy 0 Course Hero 3e Therefore the solution is y(θ) = √ 3e1−cosθ (c) dy dx ...
画像をダウンロード y=2x^2-1 y=0 x=1 x=3 154214-Y=2x^2-1 y=0 x=1 x=3
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25 ++ x^5 y^5 326321-(x/5)^2+(y/5)^2
∵ x y = 5 x 2 y 2 2xy = 25 (2) (2) – (1) gives, xy = 1 ∴ x 3 y 3 = (x y) 3 – 3xy(x y) = 5 3 – 3 × 1 × 5 = 110 ∴ x 2 y 2 = 24 – xy = 24 – 1 =...
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